BQ#3 – Unit T Concepts 1-3

• How do the graphs of sine and cosine relate to each of the others?  Emphasize asymptotes in your response.

Tangent?

Tangent is equal to sin/cos. It is undefined when cos=0. When sin=0, tangent goes through the x-axis since tan=0.

Cotangent?

Cotangent is equalled to cos/sin. In Quadrant 1, t will be positive since the sin and cos graphs are positive. If the sin=1, cotangent will have asymptotes. In Quadrant 2, cos is negative; sin is positive. In quadrant 3, cos is negative; sin is negative. Their signs cancel out to make a positive cotangent. In Quadrant 4, cos is positive; sin is negative. This will give cotangent a negative answer.

Secant?

The reciprocal of secant is 1/cos. If cos=0, sec is undefined and will not touch. However, if the cos=1, sec amplitudes will touch.

Cosecant?

The reciprocal of cosecant is 1/sin. If sin=0, cosecant is undefined and will not touch. However, if sin=1, csc amplitudes will touch.

BQ#5 – Unit T Concepts 1-3

Why do sine and cosine NOT have asymptotes, but the other four trig graphs do? Use unit circle ratios to explain.

The Unit Circle has ratios for trig functions. Sin=y/r, cos=x/r, tan=y/x, csc=r/y, sec=r/x, and cot=x/y. The asymptote is only present when the denominator is equal to 0. However, since r is always equal to 1 in the Unit Circle triangles, this will give us an actual number value for sine and cosine. For us to have an asymptote, we would have to have an undefined answer like in the other four trig graphs give us.

BQ#2 – Unit T Concept Intro

How do the trig graphs relate to the Unit Circle?
ANSWER: Trig graphs relate to the Unit Circle because we just have to imagine the Unit Circle being "unwrapped" into a straight line. This would be like the x-axis of the trig graphs. We have to imagine the Unit Circle still having its coordinates.

• Period? - Why is the period for sine and cosine 2pi, whereas the period for tangent and cotangent is pi?

ANSWER: The period of sine and cosine is 2pi because of their positives and negatives. From quadrant one through four, sine is positive, positive, negative, negative. We imagine sine on the unit circle in portions. At 0* it is 0. At 90* it is 1. At 180* it is 0. At 270* it is -1. At 360* it is 0. These are literally the points on the graph that give sine a mountain-to-valley image. For cosine it is reflected, so we start with a valley then turn into a mountain. For tangent and cotangent, the signs from quadrant one to four are positive, negative, positive, negative. Within this "unwrapped unit circle" we only see two periods. However, this kind of graph only shows us half of the period, hence, it is pi.

• Amplitude? – How does the fact that sine and cosine have amplitudes of one (and the other trig functions don’t have amplitudes) relate to what we know about the Unit Circle?

ANSWER: Sine and cosine have amplitudes of one because the Unit Circle's coordinates are at (0,1), (0,-1), (1,0), and (-1,0). If you look at (0,-1) and (0,1), these points are the graph's highest and lowest points on the graph. The amplitude is not going to pass one because that is where it reaches it's highest point, and it is at its lowest point at -1.

BQ# 1: Unit P

2. Law of Sines
SSA is ambiguous because we don't know if we will have no triangles, one triangle, or two triangles. We are only given one angle in this case. Now thinking back to the Unit Circle, we should remember how the lines on the circle are given to us by using Law of Sines when the radius is not equal to 1 as it has been given to us in Unit N.

4. Area Formula
The base is b and h is the height of the triangle. Here are are not given the height, so we have to use arcsin of the angle which, in this case, is equal to h/a. We are using opposite over hypotenuse for whatever angle we are using; in this case, it is angle C. We then take sin of the angle times 1/2ab. However, sometimes it won't have a and b given, so we have to take what is given and make sure we haves its opposite angle. All the sides must be different, so just think of all the variables in the equation being different. Here are the other formulas we can use:
A= 1/2bcsinA
A=1/2acsinB
A=absinC

http://www.compuhigh.com/demo/lesson07_files/oblique.gif

Works Cited
http://www.compuhigh.com/demo/lesson07_files/oblique.gif

I/D3: Unit Q - Pythagorean Identities

Inquiry Activity Summary

The Pythagorean is here again. We first saw it in unit N in the unit circle, and it relates to trig identities as well. Using x, y, and r, we can show that. (x^2/r^2)+(y^2/r^2)=(r^2/r^2) which is also (x^2/r^2)+(y^2/r^2)=1. This can be simplified to (x/r)^2+(y/r)^2=1. sin2x+cos2x=1 comes from the unit circle. The ratio for cosine on the unit circle is x/r. The ratio for since is y/r. Here we are going to take one of the magic 3 ordered pairs: 30 degrees. cos30 is equal to radical 3 over 2 and sin30 is equal to 1/2. Radical 3 over 2 squared is equal to 3/4. 1/2 squared is equal to 1/4. 3/4+1/4=1 which is where you get the one on the right side. Since we squared these fractions, we have to show it in our identities also. This identity is actually the Pythagorean theorem moved around, hence it is also called the Pythagorean identity. Keep in mind that an identity is "a proven fact and formula that is always true." This tactic works with any degree from the magic 3.

We can also derive the secant and tangent from sin2x+cos2x=1. If you divide all of that by cos2x, you will end up with tan2x+1=sec2x. With tanx=sinx/cosx, multiply the left and right sides by themselves to get a squared value for both. tanx*tanx=(sinx/cosx)(sinx/cos). In the end you will get tan2x=sin2x/cos2x.

Inquiry Activity Reflection

1. The connections that I see between Units N, O, P, and Q so far are that they all relate to triangle and they all use the six trig functions.
2. If I had to describe trigonometry in THREE words, they would be challenging, connected, and unexceptional.

WPP#13-14: Unit P Concept 6 & 7 - Law of Sines/Cosines

This WPP 13-14 was made in collaboration with Tracey Pham. Please visit the other awesome posts on her blog by going HERE.

WPP #12 Unit O Concept 10: Angle of Depression and Elevation

Elevation
Yoshi is filming his music video and wants to have his shot at the beach. For one of his shots, he is going to be standing at the top of a lighthouse while the camera will be on the floor 18 feet away from the lighthouse. The angle of elevation from the camera lense to the top of the lighthouse is 34*14'. What is the height of the lighthouse?

Answer: 12.25 m

Elevation

Depression

Yoshi is now on the other side of the lighthouse. He hears his fans cheering him on from below 36.8 m away and looks straight at them and waves. What is the angle of depression if he was standing on the same leveled lighthouse? (Hint: disregard the orange-ish lines labeling 12.25 m; the lighthouse from Yoshi to the floor is 12.25)

Answer: 34.24*

Depression


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